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Pool 'm Up (Pool 'm Up.exe) - all versions. Pool 'm Up is a pool simulation game. Pool m Up is a straightforward pool game with a few added things. Pool 'm Up (Pool 'm Up.exe) - all versions. Pool 'm Up is a pool simulation game. Pool m Up is a straightforward pool game with a few added things.

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When the primary OSD receives an acknowledgment from the secondary OSD(s) and the primary OSD itself completes its write operation, it acknowledges a successful write operation to the Ceph client. With the ability to perform data replication on behalf of Ceph clients, Ceph OSD Daemons relieve Ceph clients from that duty, while ensuring high data availability and data safety. The primary OSD and the secondary OSDs are typically configured to be in separate failure domains (i.e., rows, racks, nodes, etc.). CRUSH computes the ID(s) of the secondary OSD(s) with consideration for the failure domains. 1.5.2. Erasure-coded I/O Like replicated pools, in an erasure-coded pool the primary OSD in the up set receives all write operations. In replicated pools, Ceph makes a deep copy of each object in the placement group on the secondary OSD(s) in the set. For erasure coding, the process is a bit different. An erasure coded pool stores each object as K+M chunks. It is divided into K data chunks and M coding chunks. The pool is configured to have a size of K+M so that each chunk is stored in an OSD in the acting set. The rank of the chunk is stored as an attribute of the object. The primary OSD is responsible for encoding the payload into K+M chunks and sends them to the other OSDs. It is also responsible for maintaining an authoritative version of the placement group logs. For instance an erasure coded pool is created to use five OSDs (K+M = Four OSDs (k+m=4) and Ceph can lose one of those OSDs without losing data. The default erasure code profile can sustain the loss of a single OSD. It is equivalent to a replicated pool with a size two, but requires 1.5 TB instead of 2 TB to store 1 TB of data. To display the default profile use the following command: $ ceph osd erasure-code-profile get defaultk=2m=2plugin=jerasuretechnique=reed_sol_van You can create a new profile to improve redundancy without increasing raw storage requirements. For instance, a profile with k=8 and m=4 can sustain the loss of four (m=4) OSDs by distributing an object on 12 (k+m=12) OSDs. Ceph divides the object into 8 chunks and computes 4 coding chunks for recovery. For example, if the object size is 8 MB, each data chunk is 1 MB and each coding chunk has the same size as the data chunk, that is also 1 MB. The object will not be lost even if four OSDs fail simultaneously. The most important parameters of the profile are k, m and crush-failure-domain, because they define the storage overhead and the data durability. Choosing the correct profile is important because you cannot change the profile after you create the pool. To modify a profile, you must create a new pool with a different profile and migrate the objects from the old pool to the new pool. For instance, if the desired architecture must sustain the loss of two racks with a storage overhead of 40% overhead, the following profile can be defined: $ ceph osd erasure-code-profile set myprofile \ k=4 \ m=2 \ crush-failure-domain=rack$ ceph osd pool create ecpool 12 12 erasure *myprofile*$ echo ABCDEFGHIJKL | rados --pool ecpool put NYAN -$ rados --pool ecpool get NYAN -ABCDEFGHIJKL The primary OSD will divide the NYAN object into four (k=4) data chunks and create two additional chunks (m=2). The value of m defines how many OSDs can be lost simultaneously without losing any data. The crush-failure-domain=rack will create a CRUSH rule that ensures no two chunks are stored in the same rack. Red Hat supports the following jerasure coding values for k, and m: k=8 m=3 k=8 m=4 k=4 m=2 If the number of OSDs lost equals the number of coding chunks (m), some placement groups in the erasure coding pool will go into incomplete state. If the number of OSDs lost is less than m, no placement groups will go into incomplete state. In either situation, no data loss will occur. If placement groups are in incomplete state, temporarily reducing min_size of an erasure coded pool will allow recovery. 5.2.1. OSD erasure-code-profile Set To create a new erasure code profile: ceph osd erasure-code-profile set \ [] \ []

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InitVal:endVal,opts); statements; end uses opts to specify the resources to use in evaluating statements in the loop body. Create a set of parfor options using the parforOptions function. With this approach, you can run parfor on a cluster without first creating a parallel pool and control how parfor partitions the iterations into subranges for the workers.parfor (loopVar = initVal:endVal,cluster); statements; end executes statements on workers in cluster without creating a parallel pool. This is equivalent to executing parfor (loopVar = initVal:endVal,parforOptions(cluster)); statements; end.exampleExamplescollapse allConvert a for-Loop Into a parfor-Loop Create a parfor-loop for a computationally intensive task and measure the resulting speedup. In the MATLAB Editor, enter the following for-loop. To measure the time elapsed, add tic and toc.ticn = 200;A = 500;a = zeros(1,n);for i = 1:n a(i) = max(abs(eig(rand(A))));endtocRun the script, and note the elapsed time.Elapsed time is 31.935373 seconds.In the script, replace the for-loop with a parfor-loop.ticn = 200;A = 500;a = zeros(1,n);parfor i = 1:n a(i) = max(abs(eig(rand(A))));endtocRun the new script, and run it again. The first run is slower than the second run, because the parallel pool has to be started, and you have to make the code available to the workers. Note the elapsed time for the second run.By default, MATLAB automatically opens a parallel pool of workers on your local machine.Elapsed time is 10.760068 seconds. Observe that you speed up your calculation by converting the for-loop into a parfor-loop on four workers. You might reduce the elapsed time further by increasing the number of workers in your parallel pool. For more information, see Convert for-Loops Into parfor-Loops and Scale Up parfor-Loops to Cluster and Cloud.Test parfor-Loops by Switching Between Parallel and Serial Execution You can specify the maximum number of workers M for a parfor-loop. Set M = 0 to run the body of the loop in the desktop MATLAB, without using workers, even if a pool is open. When M = 0, MATLAB still executes the loop body in a nondeterministic order, but not in parallel, so that you can check whether your parfor-loops are independent and suitable to run on workers. This is the simplest way to allow you to debug the contents of a parfor-loop. You cannot set breakpoints directly in the body of the parfor-loop, but you can set breakpoints in functions called from the body of the parfor-loop. Specify M = 0 to run the body of a. Pool 'm Up (Pool 'm Up.exe) - all versions. Pool 'm Up is a pool simulation game. Pool m Up is a straightforward pool game with a few added things.

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Underlying volume GUID for a mount point will be the same each time the mount point re-mounts. [u] Improved start up when one/all drives detached from the pool. [u] Improved polling load (aka less CPU usage) when waiting on drives to reconnect to the pool. [n] Pools can now be switched "offline", this causes all mount points to be dismounted until the user switched back to "online" mode. Option available along the top banner within the Drive Bender Manager. [u] The pool file system health check now runs every 7 days and no sooner, even after a restart. [u] The location of temp and log files has changed, there are now located in "\ProgramData\Division-M\Drive Bender". [b] Folders pending delete may not get deleted, this can result in "orphaned duplicate" messages being generated. [b] If the pool is in fault tolerant mode, the Drive Bender Manager can cause an excessive load on the pool. [b] When using a landing zone, and a file is sent to the recycle bin before it has been moved from the landing zone, the file remains in the recycle bin on the landing zone drive until emptied. As part of the clearing process, the recycle bin is now checked and any files found are now moved from the landing zone drive. [u] Improved target drive selection under "Balanced" mode. [b] The minimum free space setting from drives can fail in some conditions. [u] When upgrading, the installer will now uninstall the existing driver version first before installing the newer version (this happens automatically). Release v2.3.9.0 release (2015-08-17) [u] Improved overall start up performance when one or more drives have not connected. [u] Add registry value to override for email "sender", under "HKEY_LOCAL_MACHINE\SOFTWARE\Division-M\Drive Bender" as a new string value "Email From Override". [b] When deleting a pool This repository was archived by the owner on Apr 24, 2022. It is now read-only. This repository was archived by the owner on Apr 24, 2022. It is now read-only. DescriptionWith version 0.17.0 I get the following error:ethminer.exe --api-port -4004 -P stratum+tcp://**********.multipoolminer:[email protected]:20585 --opencl --opencl-devices 0 m 23:20:30 main ethminer 0.17.0 m 23:20:30 main Build: windows/release i 23:20:31 main Found suitable OpenCL device [Baffin] with 2.000 GB of GPU memory i 23:20:31 main Found suitable OpenCL device [Ellesmere] with 4.000 GB of GPU memory i 23:20:31 main Configured pool europe.ethash-hub.miningpoolhub.com:20585 i 23:20:31 main Api server listening on port 4004. i 23:20:31 main Selected pool europe.ethash-hub.miningpoolhub.com:20585 i 23:20:31 stratum Stratum mode detected: STRATUM i 23:20:31 stratum Subscribed! i 23:20:31 stratum Job: #29017dcf... [18.197.166.72:20585] i 23:20:31 stratum Pool difficulty: 8.60K megahash i 23:20:31 stratum New epoch 138 i 23:20:31 stratum Worker not authorized ************* i 23:20:31 main Disconnected from [18.197.166.72:20585] i 23:20:32 main No more connections to try. Exiting... i 23:20:33 main Terminated!Environment: Windows 10 x64, latest AMD & NVIDIA driverError is independent of selected GPU model / makerThe same command works perfectly on version 0.16.2:ethminer.exe --api-port -4004 -P stratum+tcp://**********.multipoolminer:[email protected]:20585 --opencl --opencl-devices 0 m 23:22:46 main ethminer 0.16.2 m 23:22:46 main Build: windows/release i 23:22:46 main Found suitable OpenCL device [Baffin] with 2.000 GB of GPU memory i 23:22:46 main Found suitable OpenCL device [Ellesmere] with 4.000 GB of GPU memory i 23:22:46 main Configured pool europe.ethash-hub.miningpoolhub.com:20585 i 23:22:46 main Api server listening on port 4004. i 23:22:46 main Selected pool europe.ethash-hub.miningpoolhub.com:20585 i 23:22:46 stratum Stratum mode detected: STRATUM i 23:22:47 stratum Subscribed! i 23:22:47 stratum Job: #806d3c95... europe.ethash-hub.miningpoolhub.com [18.197.166.72:20585] i 23:22:47 stratum Pool difficulty: 8.60K megahash i 23:22:47 stratum New epoch 138 i 23:22:47 stratum Authorized worker ***********.multipoolminer i 23:22:47 stratum Established connection with europe.ethash-hub.miningpoolhub.com:20585 at [18.197.166.72:20585] i 23:22:47 stratum Spinning up miners...

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Is negligible?Solution:Given details are,Size of one brick = 25cm × 10cm × 8cmDimensions of wall = 5m × 3m × 16cm = 500 cm × 300 cm × 16cmWe know that,Number of bricks required to build a wall = volume of wall / volume of one brick= (500×300×16) / (25×10×8)= 1200 bricks∴ 1200 bricks are required to build the wall.12. A village, having a population of 4000, required 150 litres water per head per day. It has a tank which is 20 m long, 15 m broad and 6 m high. For how many days will the water of this tank last?Solution:Given details are,Population of village = 4000Dimensions of water tank = 20m × 15m × 6mWater required per head per day = 150 litresTotal requirement of water per day = 150 × 4000 = 600000 litresVolume of water tank = l × b × h= 20 × 15 × 6= 1800m3= 1800000 litresWe know that,Number of days water last in the tank = volume of tank / total requirement= 1800000/600000= 3 days∴ Water in the tank last for 3 days.13. A rectangular field is 70 m long and 60 m broad. A well of dimensions 14 m × 8 m × 6 m is dug outside the field and the earth dug-out from this well is spread evenly on the field. How much will the earth level rise?Solution:Given details are,Dimensions of rectangular field = 70m × 60mDimensions of well = 14m × 8m × 6mAmount of earth dug out from well (volume) = l × b × h= 14 × 8 × 6 = 672m3We know that,Rise in earth level = dimensions of rectangular field / amount of earth dug up= (70×60) / 672= 0.16m= 16cm∴ Rise in earth level on a rectangular field is 16cm.14. A swimming pool is 250 m long and 130 m wide. 3250 cubic metres of water is pumped into it. Find the rise in the level of water.Solution:Given details are,Dimensions of swimming pool = 250 m × 130mVolume of water pumped in it = 3250 m3We know that,Rise in water level in pool = volume of water pumped / dimensions of swimming pool= 3250/(250×130)= 0.1m∴ Rise in level of water is 0.1m15. A beam 5 m long and 40 cm wide contains 0.6 cubic metre of wood. How thick is the beam?Solution:Given details are,Length of beam = 5 mWidth of beam = 40 cm = 0.4 mVolume of wood in beam = 0.6 m3Let thickness of beam be ‘h’ mWe know that,Volume = l × b × hh = volume/(l × b)= 0.6/(5×0.4)= 0.3m∴ Thickness of the beam is 0.3m16. The rainfall on a certain day was 6 cm. How many litres of water fell on 3 hectares of field on that day?Solution:Given details are,Area of field = 3 hectare = 3×10000 m2 = 30000 m2Depth of water on the field = 6cm = 6/100 = 0.06mVolume of water = area of field × depth of water= 30000 × 0.06= 1800 m3We know

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Pool name and creating an I/O context. Storage strategies are invisible to the Ceph client in all but capacity and performance. Similarly, the complexities of Ceph clients (mapping objects into a block device representation, providing an S3/Swift RESTful service) are invisible to the Ceph storage cluster. A pool provides you with: Resilience: You can set how many OSD are allowed to fail without losing data. For replicated pools, it is the desired number of copies/replicas of an object. A typical configuration stores an object and one additional copy (i.e., size = 2), but you can determine the number of copies/replicas. For erasure coded pools, it is the number of coding chunks (i.e. m=2 in the erasure code profile) Placement Groups: You can set the number of placement groups for the pool. A typical configuration uses approximately 50-100 placement groups per OSD to provide optimal balancing without using up too many computing resources. When setting up multiple pools, be careful to ensure you set a reasonable number of placement groups for both the pool and the cluster as a whole. CRUSH Rules: When you store data in a pool, a CRUSH ruleset mapped to the pool enables CRUSH to identify a rule for the placement of each object and its replicas (or chunks for erasure coded pools) in your cluster. You can create a custom CRUSH rule for your pool. Snapshots: When you create snapshots with ceph osd pool mksnap, you effectively take a snapshot of a particular pool. Quotas: When. Pool 'm Up (Pool 'm Up.exe) - all versions. Pool 'm Up is a pool simulation game. Pool m Up is a straightforward pool game with a few added things.

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Hat recommends min_size for erasure-coded pools to be K+1 or more to prevent loss of writes and data. Erasure coding uses storage capacity more efficiently than replication. The n-replication approach maintains n copies of an object (3x by default in Ceph), whereas erasure coding maintains only k + m chunks. For example, 3 data and 2 coding chunks use 1.5x the storage space of the original object. While erasure coding uses less storage overhead than replication, the erasure code algorithm uses more RAM and CPU than replication when it accesses or recovers objects. Erasure coding is advantageous when data storage must be durable and fault tolerant, but do not require fast read performance (for example, cold storage, historical records, and so on). For the mathematical and detailed explanation on how erasure code works in Ceph, see the Ceph Erasure Coding section in the Architecture Guide for Red Hat Ceph Storage 5. Ceph creates a default erasure code profile when initializing a cluster with k=2 and m=2, This mean that Ceph will spread the object data over four OSDs (k+m == 4) and Ceph can lose one of those OSDs without losing data. To know more about erasure code profiling see the Erasure Code Profiles section. Configure only the .rgw.buckets pool as erasure-coded and all other Ceph Object Gateway pools as replicated, otherwise an attempt to create a new bucket fails with the following error: set_req_state_err err_no=95 resorting to 500 The reason for this is that erasure-coded pools do not support the omap operations and certain Ceph Object Gateway metadata pools require the omap support. 5.1. Creating a Sample Erasure-coded Pool The ceph osd pool create command creates an erasure-coded pool with the default profile, unless another profile is specified. Profiles define the redundancy of data by setting two parameters, k, and m. These parameters define the number of chunks a piece of data is split and the number of coding chunks are created. The simplest erasure coded pool is equivalent to RAID5 and requires at least three hosts: $ ceph osd pool create ecpool 32 32 erasurepool 'ecpool' created$ echo ABCDEFGHI | rados --pool ecpool put NYAN -$ rados --pool ecpool get NYAN -ABCDEFGHI The 32 in pool create stands for the number of placement groups. 5.2. Erasure Code Profiles Ceph defines an erasure-coded pool with a profile. Ceph uses a profile when creating an erasure-coded pool and the associated CRUSH rule. Ceph creates a default erasure code profile when initializing a cluster and it provides the same level of redundancy as two copies in a replicated pool. However, it uses 25% less storage capacity. The default profiles define k=2 and m=2, meaning Ceph will spread the object data over