Kpa aktier

Widgets i Windows er interaktive elementer, der viser dynamisk indhold og giver hurtig adgang til forskellige apps og funktioner. Du kan få vist din placerings aktuelle vejrforhold direkte på proceslinjen og holde markøren over ikonet for at få vist præcise, scannelige oplysninger om emner som sport, aktier, lokale nyheder og nyheder. Widgets er designet til at hjælpe dig med at holde dig informeret og organiseret ved hurtigt at præsentere tilpassede oplysninger. Widgets vises på widgets-tavlen, som indeholder en samling kort, der hver repræsenterer en widget med relevante oplysninger og handlinger, der er relateret til en app. På widgets-tavlen kan du finde, fastgøre, frigøre, arrangere, tilpasse størrelsen på og tilpasse widgets for at afspejle dine interesser. Widgets kan vise en række forskellige oplysninger, herunder: Vejr: Aktuelle forhold og prognoser for din valgte placering Nyheder: Seneste overskrifter fra kilder, du har tillid til Trafik: Trafikopdateringer til din rute i realtid Aktier: Opdateringer på dine foretrukne aktier og markedstendenser Billeder: Et slideshow med dine seneste billeder Bemærk!: Widgets er ikke beregnet til at erstatte komplette programmer, men er en nem metode til at få adgang til vigtige oplysninger og udføre hurtige handlinger uden at starte den tilknyttede app eller det tilknyttede websted. De opdateres dynamisk hele dagen for at holde indholdet opdateret og relevant. Du kan få adgang til widgets-tavlen enten ved at: Hold markøren over eller vælg området Widgets på proceslinjen Brug af genvejen Windows-tast​​​​​​​ + W Stryge fra siden af skærmen Konfigurer indstillinger for widgets I de følgende afsnit beskrives almindelige

View larger Reference SC-900 Manufacturer: Spectrum Technologies Condition: New ◆ Soil compaction prevents moisture penetration, reduces fertilizer and chemical uptake and hinders plant root growth. In some cases, yield losses can run as high as 30% due to compaction. This electronic soil compaction meter is the most versatile compaction meter on the market.◆ Soil depth readings are determined by a sonic depth sensor.Cone index values are measured by a load cell sensor and can be displayed in PSI or kPa.◆ Ref: 6110FS Consulta este producto Print Overview Specifications Accessories and Options Data sheet Download Type of Instrument Penetrometer/Compactometer The Sensor measures: Soil Compaction ► The main source of yield loss in agriculture, soil compaction, prevent the penetration of moisture, reduces the use of chemical fertilizers and hinders the growth of the root of plants.► That is why the soil compaction meter Fieldscout SC900 measures and records your soil compaction in digital form quickly and effectively. Sometimes, the loss of performance due to compaction can reach 30.► This digital penetrometer is an easy and powerful instrument to measure, record, and analyze the compaction of the soil in their fields.► A unique sonic depth sensor provides readings of the depth in increments of 2, 5cm and a load cell measures the resistance to penetration.► The data of compaction is read digitally in PSI, or kPa. A recorder built-in datalogger tip eliminates the need to manually register data.► Compatible with GPS for mapping of compaction. (Not included) Measurement Units: Cone Index (PSI or kPa)Resolution: 1 in (2.5 cm), 5 PSI (35 kPa)Accuracy: ± 0.5 in (1.25 cm) Depth, ±15 PSI (103 kPa) PressureRange: 0 to18 in (0 to 45 cm), 0 to 1,000 PSI (0 to 7,000 kPa)Battery/Life: 4 AAA alkaline batteries; approximately 12-month lifeData Logger Capacity: 772 profiles without GPS; 579 profiles with GPS 1 other products in the same category: 6490S... 1 395,00 €

The specific gravity of a certain oil is 0.82. calculate its a.Specific weight in (1b/in^3 and KPa) b. Mass density in (slugs/ ft^3 and kg/m^3)Gauth AI SolutionAnswera. Specific weight: 0.9463 lb/in^3 and 26.20 kPab. Mass density: 51.168 slugs/ft^3 and 26370.78 kg/m^3ExplanationSpecific weight is the weight per unit volume of a substance. It is calculated as specific weight = specific gravity * density of water * acceleration due to gravity.Given specific gravity = 0.82, density of water = 62.4 lb/ft^3, acceleration due to gravity = 32.2 ft/s^2.a. Specific weight in lb/in^3:Specific weight = 0.82 * 62.4 lb/ft^3 * 32.2 ft/s^2Specific weight = 1632.9984 lb/ft^3To convert lb/ft^3 to lb/in^3, we use the conversion factor: 1 ft^3 = 1728 in^3.Specific weight in lb/in^3 = 1632.9984 lb/ft^3 * (1 ft^3 / 1728 in^3)Specific weight in lb/in^3 = 0.9463 lb/in^3b. Specific weight in kPa:1 lb/in^3 = 27.6799 kPaSpecific weight in kPa = 0.9463 lb/in^3 * 27.6799 kPa/lb/in^3Specific weight in kPa = 26.20 kPaMass density is the mass per unit volume of a substance. It is calculated as mass density = specific gravity * density of water.Given specific gravity = 0.82, density of water = 62.4 lb/ft^3.b. Mass density in slugs/ft^3:Mass density = 0.82 * 62.4 lb/ft^3Mass density = 51.168 slugs/ft^3To convert slugs/ft^3 to kg/m^3, we use the conversion factor: 1 slug/ft^3 = 515.378818 kg/m^3.Mass density in kg/m^3 = 51.168 slugs/ft^3 * (515.378818 kg/m^3 / 1 slug/ft^3)Mass density in kg/m^3 = 26370.78 kg/m^3Gauth AI ProLimited offer! Enjoy unlimited answers for free.Previous questionNext question

EngineeringMechanical EngineeringMechanical Engineering questions and answersAn air-standard cycle Diesel engine has a compression ratio of 20 and a cut-off ratio of 5. If the intake air pressure and temperature are 100 kPa and 27 °C. respectively. calculate the net work of the cycle (in kJ/kg). For air, take k=1.4 and c, =1.006 kJ/kg-K. Your solution’s ready to go!Our expert help has broken down your problem into an easy-to-learn solution you can count on.See AnswerQuestion: An air-standard cycle Diesel engine has a compression ratio of 20 and a cut-off ratio of 5. If the intake air pressure and temperature are 100 kPa and 27 °C. respectively. calculate the net work of the cycle (in kJ/kg). For air, take k=1.4 and c, =1.006 kJ/kg-K. Show transcribed image textTranscribed image text: An air-standard cycle Diesel engine has a compression ratio of 20 and a cut-off ratio of 5. If the intake air pressure and temperature are 100 kPa and 27 °C. respectively. calculate the net work of the cycle (in kJ/kg). For air, take k=1.4 and c, =1.006 kJ/kg-K.

EngineeringMechanical EngineeringMechanical Engineering questions and answersA turbine operates adiabatically with steam exiting at T2 and P2 a mass flow rate m˙ and a turbine efficiency η. Determine the temperature and pressure at the inlet that would provide the highest powery some interpolations may be required.Reminder: For any information token from steam tables (excel or textbook), provide screenshots and highlight theThis problem has been solved!You'll get a detailed solution from a subject matter expert that helps you learn core concepts.See AnswerQuestion: A turbine operates adiabatically with steam exiting at T2 and P2 a mass flow rate m˙ and a turbine efficiency η. Determine the temperature and pressure at the inlet that would provide the highest powery some interpolations may be required.Reminder: For any information token from steam tables (excel or textbook), provide screenshots and highlight theA turbine operates adiabatically with steam exiting at T2 and P2 a mass flow rate m˙ and a turbine efficiency η. Determine the temperature and pressure at the inlet that would provide the highest powery some interpolations may be required.Reminder: For any information token from steam tables (excel or textbook), provide screenshots and highlight the information used on the screenshot. Data: T2=700°CT1=3°Cm=80kgsecxy=0.85η=0.8Notes the exit values already inctuded the efficiencyA turbine operates adiabatically with superheated steam entering at 425°C and 8000 KPa with a mass flow rate of 100kgsec. Inlet properties are: H1=3209.5KJKg,S1=6.4684KJKgK. If the discharge (or exit) pressure is 30 KPa , find the following properties at the exit.You will find your answers using data from the following table. Highlight the points used in the table. Units for V are cm3g, for U and H are KJkg and for A turbine operates adiabatically with superheated steam entering at 425°C and 8000 KPa with a mass flow rate of 100kgsec. Inlet properties are: H1=3209.5KJKg,S1=6.4684KJKgK. If the discharge (or exit) pressure is 30 KPa , find the following properties at the exit.You will find your answers using data from the following table. Highlight the points used in the table. Units for V are cm3g, for U and H are KJkg and for TABLE E. 2 Properties of Superheated

Climatic Data Location Province: Ground snow load Ss: Rain Load Sr: Factors Importance factor --> Importance Factor, Is: Factors --> Basic Roof Factor, Cb: If Cb left blank, provide the dimensions in the roof geometry to compute Cb Accumulation Factor, Ca: (If Caleft blank, Ca will be computed assuming gable roof) Roof Geometry Pitch: /12 Slippery: Roof Plan dimensions Dimensions used to calculated Cb if Cb left empty. Longer dimension, l: m Shorter dimension, w: m Specified Snow Load [4.1.6.2] S = Is[Ss(CbCwCsCa)+Sr] Factors User input values: Importance Factors: ULS: Is = 0.8 SLS: Is = 0.9 Cb = 0.8 (based on input CbRoof slope = 0 degrees Slope Factor For non-slippery roof: Slope s = 1 [Table A-4.1.6.9] Snow on Gable Roofs Load Case I Same load on both upwind and downwind sides. ULS: Cw = 1 Ca = 1 S = 1.44 kPa ( 30.1 psf ) SLS: Cw = 1 Ca = 1 S = 1.62 kPa ( 33.8 psf ) Load Case II Load Case II does not apply to gable roofs with slopes of 15 degrees or less.