Brackets 0 44

Marks )ASCII code 35 = # ( Number sign )ASCII code 36 = $ ( Dollar sign )ASCII code 37 = % ( Percent sign )ASCII code 38 = & ( Ampersand )ASCII code 39 = ' ( Single quote or Apostrophe )ASCII code 40 = ( ( round brackets or parentheses, opening round bracket )ASCII code 41 = ) ( parentheses or round brackets, closing parentheses )ASCII code 42 = * ( Asterisk )ASCII code 43 = + ( Plus sign )ASCII code 44 = , ( Comma )ASCII code 45 = - ( Hyphen , minus sign )ASCII code 46 = . ( Dot, full stop )ASCII code 47 = / ( Slash , forward slash , fraction bar , division slash )ASCII code 48 = 0 ( number zero )ASCII code 49 = 1 ( number one )ASCII code 50 = 2 ( number two )ASCII code 51 = 3 ( number three )ASCII code 52 = 4 ( number four )ASCII code 53 = 5 ( number five )ASCII code 54 = 6 ( number six )ASCII code 55 = 7 ( number seven )ASCII code 56 = 8 ( number eight )ASCII code 57 = 9 ( number nine )ASCII code 58 = : ( Colon )ASCII code 59 = ; ( Semicolon )ASCII code 60 = ( Less-than sign )ASCII code 61 = = ( Equals sign )ASCII code 62 = > ( Greater-than sign ; Inequality )ASCII code 63 = ? ( Question

Can be simplified to:Ka = H+2[CH3COOH]{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" role="math" height="44" width="87" alt="fraction numerator open square brackets straight H to the power of plus close square brackets squared over denominator stretchy left square bracket CH subscript 3 COOH stretchy right square bracket end fraction">Step 4: Substitute the values into the expression to find Ka:Ka = 1.32×10-32[0.100]{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" role="math" height="42" width="98" alt="fraction numerator open square brackets 1.32 cross times 10 to the power of negative 3 end exponent close square brackets squared over denominator stretchy left square bracket 0.100 stretchy right square bracket end fraction">Ka = 1.74 x 10-5Step 5: Determine the units of Ka:Ka = mol dm-32mol dm-3{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" role="math" height="44" width="85" alt="fraction numerator open square brackets mol space dm to the power of negative 3 end exponent close square brackets squared over denominator open square brackets mol space dm to the power of negative 3 end exponent close square brackets end fraction">= mol dm-3Therefore, Ka is 1.74 x 10-5 mol dm-3Step 6: Find pKa:pKa = - log10 KapKa = - log10 (1.74 x 10-5)pKa = 4.76KwThe Kw is the ionic product of waterIt is the equilibrium constant for the dissociation of water at 298 KIts value is 1.00 x 10-14 mol2 dm-6For the ionisation of water, the equilibrium expression to find Kw is:H2O (l) ⇌ H+ (aq) + OH- (aq)Kw = [H+] [OH-][H2O]{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" role="math" height="43" width="88" alt="fraction numerator stretchy left square bracket H to the power of plus stretchy right square bracket bold space stretchy left

(foo) { case 0: output += 'So '; case 1: output += 'What '; output += 'Is '; case 2: output += 'Your '; case 3: output += 'Name'; case 4: output += '?'; console.log(output); break; case 5: output += '!'; console.log(output); break; default: console.log('Please pick a number from 0 to 5!');} 这个例子的输出： Value Log text foo is NaN or not 1, 2, 3, 4, 5 or 0 Please pick a number from 0 to 5! 0 Output: So What Is Your Name? 1 Output: What Is Your Name? 2 Output: Your Name? 3 Output: Name? 4 Output: ? 5 Output: ! Block-scope variables within switch statements With ECMAScript 2015 (ES6) support made available in most modern browsers, there will be cases where you would want to use let and const statements to declare block-scoped variables. Take a look at this example: const action = 'say_hello';switch (action) { case 'say_hello': let message = 'hello'; console.log('0 ~5'); break; case 'say_hi': let message = 'hi'; case 6: console.log('6'); break; default: console.log('Empty action received.'); break;} This example will output the error Uncaught SyntaxError: Identifier 'message' has already been declared which you were not probably expecting. This is because the first let message = 'hello'; conflicts with second let statement let message = 'hi'; even they're within their own separate case statements case 'say_hello': and case 'say_hi':; ultimately this is due to both let statements being interpreted as duplicate declarations of the same variable name within the same block scope. We can easily fix this by wrapping our case statements with brackets: const action = 'say_hello';switch (action) { case 'say_hello': { // added brackets let message = 'hello'; console.log(message); break; } // added brackets case 'say_hi': { // added brackets let message = 'hi'; console.log(message); break; } // added brackets default: { // added brackets console.log('Empty action received.'); break; } // added brackets} This code will now output hello in the console as it should, without any errors at all. 规范 Specification Status Comment ECMAScript 3rd Edition (ECMA-262) Standard Initial definition. Implemented in JavaScript 1.2 ECMAScript 5.1 (ECMA-262)switch statement Standard ECMAScript 2015 (6th Edition, ECMA-262)switch statement Standard ECMAScript Latest Draft (ECMA-262)switch statement Draft 浏览器兼容性 The compatibility table on this page is generated from structured data. If you'd like to contribute to the data, please check out and send us a pull request. Update compatibility data on GitHub Desktop Mobile Server Chrome Edge Firefox Internet